问题：

子类继承父类，构造函数及公共属性的执行顺序是怎样的？

示例代码

[java]
<span style="font-family:Times New Roman;font-size:14px;">public class A extends C { 
    B b = new B(); 
    static H h = new H(); 
    static { 
        System.out.println("this is static tack"); 
    } 
 
    static void i() { 
        System.out.println("this is static metod"); 
    } 
 
    public A() { 
        System.out.println("this is class A"); 
 
    } 
 
    public static void main(String[] args) { 
        A a = new A(); 
    } 
} 
 
class B { 
    public B() { 
        System.out.println("this is class B"); 
    } 
} 
 
class C { 
    D d = new D(); 
    static E e = new E(); 
    final F e1 = new F(); 
    static final G e2 = new G(); 
 
    public C() { 
        System.out.println("this is class C"); 
    } 
} 
 
class D { 
    public D() { 
        System.out.println("this is class D"); 
    } 
} 
 
class E { 
    public E() { 
        System.out.println("this is class E"); 
    } 
} 
 
class F { 
    public F() { 
        System.out.println("this is class F"); 
    } 
} 
 
class G { 
    public G() { 
        System.out.println("this is class G"); 
    } 
} 
 
class H { 
    public H() { 
        System.out.println("this is class H"); 
    } 
}</span> 
执行结果：

this is class E
this is class G
this is class H
this is static tack
this is class D
this is class F
this is class C
this is class B
this is class A

执行顺序：

1、实现父类公共的静态属性或静态的块级代码

2、实现本身的公共的静态属性

3、实现父类公共属性

4、执行父类的构造方法

5、实现本身的公共属性

6、执行本身的构造函数

7、静态方法不执行

补充：

当父类有多个构造函数，若子类用super(参数信息)指明调用父类有参数的构造函数，则不执行无参数的构造方法